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49 lines
1.2 KiB
Python
49 lines
1.2 KiB
Python
1 year ago
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import math
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A = [100.012, -9.789]
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C = [100.076, -10.083]
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B = [100.043, -9.937]
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s = abs((A[0] * B[1] + B[0] * C[1] + C[0] * A[1] - A[1] * B[0] - B[1] * C[0] - C[1] * 1) / 2)
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print('s',s)
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a = abs(math.sqrt(abs(A[0] - C[0]) ** 2) + abs((A[1] - C[1]) ** 2))
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print('a',a)
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b = abs(math.sqrt(abs(B[0] - C[0]) ** 2) + abs((B[1] - C[1]) ** 2))
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print('b',b)
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c = abs(math.sqrt(a ** 2 + b ** 2))
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print('c',c)
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k = 4 * s / (a * b * c)
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print(k)
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# import numpy as np
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# def get_arc_curve(pts):
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# '''
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# 获取弧度值
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# :param pts:
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# :return:
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# '''
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#
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# # 计算弦长
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# start = np.array(pts[0])
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# end = np.array(pts[len(pts) - 1])
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# l_arc = np.sqrt(np.sum(np.power(end - start, 2)))
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#
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# # 计算弧上的点到直线的最大距离
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# # 计算公式：\frac{1}{2a}\sqrt{(a+b+c)(a+b-c)(a+c-b)(b+c-a)}
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# a = l_arc
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# b = np.sqrt(np.sum(np.power(pts - start, 2), axis=1))
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# c = np.sqrt(np.sum(np.power(pts - end, 2), axis=1))
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# dist = np.sqrt((a + b + c) * (a + b - c) * (a + c - b) * (b + c - a)) / (2 * a)
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# h = dist.max()
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#
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# # 计算曲率
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# r = ((a * a) / 4 + h * h) / (2 * h)
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#
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# return r
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#
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#
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# if __name__ == '__main__':
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# x = np.linspace(1, 100, 99).astype(np.int64)
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# y = (x ** 2)
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# xy = list(zip(x, y)) # list of points in 2D space
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# print(get_arc_curve(xy))
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